(sin A+ cos A) (sec A+ cosec A) = 2+sec A.cosec A

Asked by kotharianaiya9 | 6th Mar, 2021, 12:15: PM

Expert Answer:

To prove: (sinA + cosA)(secA + cosecA) = 2 + secA cosecA
open parentheses sinA plus cosA close parentheses open parentheses secA plus cosecA close parentheses equals open parentheses sinA plus cosA close parentheses open parentheses 1 over cosA plus 1 over sinA close parentheses equals open parentheses sinA plus cosA close parentheses squared over sinAcosA equals fraction numerator 1 plus 2 sinAcosA over denominator sinAcosA end fraction equals 2 plus secA space cosecA

Answered by Renu Varma | 9th Mar, 2021, 09:11: PM