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CBSE Class 8 Answered

simplify.
Asked by kritikarautela16.8cpsb | 05 Jun, 2021, 07:59: PM
Expert Answer
begin mathsize 16px style fraction numerator 121 cross times straight x to the power of 6 over denominator 33 cross times 3 to the power of negative 2 end exponent cross times straight x to the power of negative 5 end exponent end fraction
equals space fraction numerator 11 squared cross times straight x to the power of 6 over denominator 11 cross times 3 cross times 3 to the power of negative 2 end exponent cross times straight x to the power of negative 5 end exponent end fraction
equals 11 squared over 11 cross times straight x to the power of 6 over straight x to the power of negative 5 end exponent cross times fraction numerator 1 over denominator 3 cross times 3 to the power of negative 2 end exponent end fraction
equals 11 to the power of 2 minus 1 end exponent cross times straight x to the power of 6 minus left parenthesis negative 5 right parenthesis end exponent cross times 1 over 3 to the power of 1 plus left parenthesis negative 2 right parenthesis end exponent space space..... space straight a to the power of straight m divided by straight a to the power of straight n equals straight a to the power of straight m minus straight n space space end exponent and space straight a to the power of straight m cross times straight a to the power of straight n equals straight a to the power of straight m plus straight n space space end exponent
equals fraction numerator 11 cross times straight x to the power of 11 over denominator 3 to the power of negative 1 end exponent end fraction
equals 11 cross times 3 cross times straight x to the power of 11
equals 33 straight x to the power of 11 end style
Answered by Yasmeen Khan | 05 Jun, 2021, 10:06: PM
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