ICSE Class 10 Answered
Question no..15 pls
![question image](http://images.topperlearning.com/topper/new-ate/4750401569175094101669472890.jpg)
Asked by amansss611 | 22 Sep, 2019, 23:29: PM
Join OA, OB, OC, OD and diagonal AC.
We know that,
Angle at the centre is twice the angle at remaining remaining circumference.
![begin mathsize 16px style rightwards double arrow angle BOC space equals space 2 angle BAC space space space space space space space space space space space space space space space.... space left parenthesis 1 right parenthesis
rightwards double arrow angle AOD space equals space 2 angle ACD space space space space space space space space space space space space space space space.... space left parenthesis 2 right parenthesis
end style](https://images.topperlearning.com/topper/tinymce/cache/9dc37620aec86de504912563796354ae.png)
Since, AB || CD and AC is a transversal.
![begin mathsize 16px style angle BAC space equals space angle ACD space space space space space space space space space space space space space space space left parenthesis alternate space angles right parenthesis space space space space space space space space.... space left parenthesis 3 right parenthesis
From space left parenthesis 1 right parenthesis comma space left parenthesis 2 right parenthesis space and space left parenthesis 3 right parenthesis comma space we space get
angle BOC space equals space angle AOD
end style](https://images.topperlearning.com/topper/tinymce/cache/0630684929ecc1f17b019db760bf5de8.png)
→ AD = BC
Chords substending equal angles at the centre are equal.
Hence proved.
Answered by Yasmeen Khan | 23 Sep, 2019, 11:54: AM
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