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CBSE Class 11-commerce Answered

Question no. 24
Asked by Payal | 22 Feb, 2018, 10:05: AM
Expert Answer
begin mathsize 16px style To space find space cos open parentheses straight alpha plus straight beta close parentheses equals cosαcosβ minus sinαsinβ......... left parenthesis straight i right parenthesis
acosθ plus bsinθ equals straight c
acosθ equals straight c minus bsinθ
squaring space on space both space sides space and space simplifying
open parentheses straight b squared plus straight a squared close parentheses sin squared straight theta minus 2 bcsinθ plus straight c squared minus straight a squared equals 0
sinαsinβ equals fraction numerator straight c squared minus straight a squared over denominator straight b squared plus straight a squared end fraction
similarly
bsinθ equals straight c minus acosθ
squaring space on space both space sides comma
open parentheses straight b squared plus straight a squared close parentheses cos squared straight theta minus 2 accosθ plus straight c squared minus straight b squared equals 0
cosαcosβ equals fraction numerator straight c squared minus straight b squared over denominator straight b squared plus straight a squared end fraction
Put space it space in space left parenthesis straight i right parenthesis
you space will space get space fraction numerator straight a squared minus straight b squared over denominator straight a squared plus straight b squared end fraction end style
Answered by Sneha shidid | 22 Feb, 2018, 12:23: PM
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