CBSE Class 11-commerce Answered
Question no. 14
![question image](https://images.topperlearning.com/topper/new-ate/413120107209203221IMG20180221165606.jpg)
Asked by Payal | 21 Feb, 2018, 16:57: PM
![begin mathsize 16px style According space to space the space question space 1 comma 2 comma 3 comma.... straight p space and space
common space ratios space 1 half comma 1 third comma 1 fourth.... comma fraction numerator 1 over denominator straight p plus 1 end fraction
Sum space of space infinite space GP space equals fraction numerator straight a over denominator 1 minus straight r end fraction
Find space straight S subscript 1 comma straight S subscript 2...... straight S subscript straight p
you space get
straight S subscript 1 space equals 2 comma space straight S subscript 2 space equals 3 comma....... comma straight S subscript straight p equals straight p plus 1
From space this space we space can space observe space that space sums space are space in space AP space with space straight a equals 2 space and space straight d equals 1
straight p over 2 open square brackets 2 cross times 2 plus open parentheses straight p minus 1 close parentheses cross times 1 close square brackets equals fraction numerator straight p left parenthesis straight p plus 3 right parenthesis over denominator 2 end fraction end style](https://images.topperlearning.com/topper/tinymce/cache/3026575c98570c3771ef250047d85551.png)
Answered by Sneha shidid | 21 Feb, 2018, 17:23: PM
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