NEET Class neet Answered
Q no 2
![question image](https://images.topperlearning.com/topper/new-ate/topr_5726324316395287IMG201903250736152.jpeg)
Asked by manasvijha | 25 Mar, 2019, 07:40: AM
when a proton is released from rest, intitially it is accelerated twowards west direction due to electric field which is acting westwards
![begin mathsize 12px style stack F subscript e with rightwards arrow on top space equals space e space E with rightwards arrow on top space equals space m left parenthesis stack a subscript 0 with rightwards arrow on top space right parenthesis space space space space o r space space open vertical bar E with rightwards arrow on top close vertical bar space equals space fraction numerator space m space a subscript 0 over denominator e end fraction space space end style](https://images.topperlearning.com/topper/tinymce/cache/089e5198af58dabd01a30438d376d027.png)
when the proton is projected in North direction with velocity v0 , proton is subjected to electric field and magnetic field.
Proton is moving towards west with acceleration 3a0 . Since
force is acting in west direction and its velocity is towards north ,
![begin mathsize 12px style v with rightwards arrow on top space cross times B with rightwards arrow on top space end style](https://images.topperlearning.com/topper/tinymce/cache/7a160691682778e1b05b2c185edc2e65.png)
magnetic field is acting downward direction ( see figure )
![](https://images.topperlearning.com/topper/tinymce/imagemanager/files/83631d7acad3b8201a56c6e50ef6d43d5c9892cb9a0fb7.40680315mar2502.png)
since it is known that electric field gives an acceleration ao , additional acceleration 2ao is given by magnetic field
![begin mathsize 12px style stack F subscript m with rightwards arrow on top space equals e left parenthesis space v with rightwards arrow on top space cross times B with rightwards arrow on top right parenthesis space equals space m open parentheses 2 stack a subscript o with rightwards arrow on top close parentheses space space space space space o r space space space space space space space open vertical bar B with rightwards arrow on top close vertical bar space equals space fraction numerator 2 m space a subscript 0 over denominator e space v subscript o end fraction end style](https://images.topperlearning.com/topper/tinymce/cache/a6efa94f1bbfd2358ccef0418e1fd4d7.png)
Hence in the list of options given in the answer, (b) is the correct one
Answered by Thiyagarajan K | 25 Mar, 2019, 14:16: PM
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