Q) Let f(x) be a cubic polynomial such that f(1)=1,f(2)=2,f(3)=3 and f(4)=16. Find the value of f(5).

Asked by banerjee_milky | 5th Jun, 2017, 10:34: AM

Expert Answer:

begin mathsize 16px style Cubic space polynomial space be
straight f left parenthesis straight x right parenthesis equals ax cubed plus bx squared plus cx plus straight d
rightwards double arrow straight f left parenthesis 1 right parenthesis equals straight a plus straight b plus straight c plus straight d
rightwards double arrow straight a plus straight b plus straight c plus straight d equals 1
rightwards double arrow straight f left parenthesis 2 right parenthesis equals 8 straight a plus 4 straight b plus 2 straight c plus straight d
rightwards double arrow 8 straight a plus 4 straight b plus 2 straight c plus straight d equals 2
rightwards double arrow straight f left parenthesis 3 right parenthesis equals 27 straight a plus 9 straight b plus 3 straight c plus straight d
rightwards double arrow 27 straight a plus 9 straight b plus 3 straight c plus straight d equals 3
rightwards double arrow straight f left parenthesis 4 right parenthesis equals 64 straight a plus 16 straight b plus 4 straight c plus straight d
64 straight a plus 16 straight b plus 4 straight c plus straight d equals 16
Solving space these space equations space simultaneously space you space will space get space value space of
straight a comma straight b comma straight c comma straight d.
and space then space find space the space value space of space straight f left parenthesis 5 right parenthesis space which space is space 293. end style

Answered by Sneha shidid | 5th Jun, 2017, 11:53: AM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.