JEE Class main Answered
P.S: Please explain all options
Asked by g_archanasharma | 06 Apr, 2019, 07:25: AM
Expert Answer
The given compounds are
1) Na2[CuCl4]
2) K4[Fe(CN)6]
3) Na2[CdCl4]
4) Na2[CrO4]
The outer electronic configuration of Cu2+, Fe2+ and Cr2+ is 3d9, 3d6 and 3d5 respectively.
That is they contains 1, 4 and 4 unpaired electrons respectively.
But, in Cd2+ the outer shell is completely filled.(4d10).
Hence, Na2[CdCl4] is colourless.
Answered by Varsha | 07 Apr, 2019, 19:48: PM
Application Videos
Concept Videos
JEE main - Chemistry
Asked by neerajavuppala1983 | 23 Jul, 2024, 22:49: PM
ANSWERED BY EXPERT
JEE main - Chemistry
Asked by tanniruv133 | 03 Jul, 2024, 18:50: PM
ANSWERED BY EXPERT
JEE main - Chemistry
Asked by heyyyyy | 12 Jun, 2024, 19:18: PM
ANSWERED BY EXPERT
JEE main - Chemistry
Asked by hv5594265 | 12 Jun, 2024, 11:59: AM
ANSWERED BY EXPERT
JEE main - Chemistry
Asked by rupalibhange1987 | 11 Jun, 2024, 20:00: PM
ANSWERED BY EXPERT
JEE main - Chemistry
Asked by gajju8493 | 11 Jun, 2024, 15:09: PM
ANSWERED BY EXPERT
JEE main - Chemistry
Asked by chakrabortymithu041 | 29 May, 2024, 18:45: PM
ANSWERED BY EXPERT