prove that:

sin^3/cosA + sinAcosA = tanA

Asked by Vru23 | 28th Jul, 2020, 11:18: PM

Expert Answer:

To prove: sin3A/cosA + sinAcosA = tanA

LHS equals fraction numerator sin cubed straight A over denominator cosA end fraction plus sinA space cosA
equals fraction numerator sin cubed straight A over denominator cosA end fraction plus fraction numerator sinA space cos squared straight A over denominator cosA end fraction
equals fraction numerator sin cubed straight A plus sinA space cos squared straight A over denominator cosA end fraction
equals fraction numerator sinA open parentheses sin squared straight A plus cos squared straight A close parentheses over denominator cosA end fraction
equals sinA over cosA
equals tanA
equals RHS
Hence comma space fraction numerator sin cubed straight A over denominator cosA end fraction plus sinA space cosA equals tanA

Answered by Renu Varma | 29th Jul, 2020, 10:38: AM