prove that 3(sinA-cosA)^⁴+6(sinA+cosA)^²+(sin^⁶A+cos^⁶A)=14
Asked by gaddamyashwanthr
| 21st Sep, 2020,
09:00: PM
Expert Answer:
To prove: 3(sinA-cosA)4 + 6(sinA+cosA)2 + 4(sin6A+cos6A) = 13
Answered by Renu Varma
| 22nd Sep, 2020,
12:06: PM
Concept Videos
- (cosec A -sinA) (sec A -cosA)=1/tanA cot A
- sec²a.cosec²a = tan²a + cot²a+ 2
- (sin A+ cos A) (sec A+ cosec A) = 2+sec A.cosec A
- tan2-sin2=tan2.sin2
- cot2 A - cos2 A = cot2 A × cos2 A
- Prove that √1+cosø/1 -cosø + √1-cosø/1+cosø = 2cosecø
- tan^2 a - sin^2 a =
- 1st question please solve it !
- prove that: sin^3/cosA + sinAcosA = tanA
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change