prove that 3(sinA-cosA)^⁴+6(sinA+cosA)^²+(sin^⁶A+cos^⁶A)=14
Asked by gaddamyashwanthr | 21st Sep, 2020, 09:00: PM
Expert Answer:
To prove: 3(sinA-cosA)4 + 6(sinA+cosA)2 + 4(sin6A+cos6A) = 13
Answered by Renu Varma | 22nd Sep, 2020, 12:06: PM
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