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position of a particle moving in a straight line given by y= 3t^3+3t^2+5 then find acceleration of the particle at Time t=2s
Asked by Pariharhingoliwala | 30 Sep, 2021, 08:06: AM
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position, y = 3 t3 + 3 t2 + 5   ........................... (1)
 
velocity as a function of time is obtained by differentiating eqn.(1)
 
velocity v = dy/dt = 9 t2 + 6 t ..........................( 2 )
 
acceleration as a function of time is obtained by differentiating eqn.(2)
 
acceleration a = d2y / dt2 = 18 t + 6
Answered by Thiyagarajan K | 30 Sep, 2021, 08:17: AM
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