plz tell me if my answer is right or not

Asked by sonalchandra | 12th Sep, 2010, 11:30: PM

Expert Answer:

NO.
Put logx = y, then dx/x = dy
∫dx/(x (logx)m) = ∫dy/ym = y -m+1/(-m+1)  + C = (1 - m)/(logx)1 - m + C.
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Answered by  | 13th Sep, 2010, 10:29: AM

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