CBSE Class 12-science Answered
Plz solve this sum
Asked by | 09 Feb, 2010, 06:18: AM
Expert Answer
(tannx + tann-2x)dx, and the limits are 0 to π/4
tannx + tann-2x = tannx(1 + 1/tan2x) = tannx((tan2x + 1)/tan2x) = tann-2(sec2x)
(tannx + tann-2x)dx = tann-2(sec2x) dx
Put tanx = y
sec2xdx = dy, and the limits x = 0, y = 0 and x = π/4, y = 1.
yn-2dy = yn-1/(n-1) + c
Put the limits,
yn-2dy = 1/(n-1), where n is an integer except 1, i.e. n 
N - {1}
Regards,
Team,
TopperLearning.
Answered by | 09 Feb, 2010, 10:14: AM
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