CBSE Class 12-science Answered
Plz solve this sum
Asked by | 05 Feb, 2010, 04:56: AM
Expert Answer
[(a-x)/(a+x)]1/2 = [(a-x)2/(a2-x2)]1/2
Put x = a siny and the limits x = -a then y = 3π/2, x = a then y = π/2
dx = a cosy dy
[(a - asiny)2/(a2-(a siny)2)]1/2
= (1 - siny)/cosy
dx [(a-x)/(a+x)]1/2 = (1 - siny)a cosy dy /cosy = (a - a siny)dy
= ay + a cosy
Put the limits, cos term goes zero.
= a((π/2) - (3π/2)) + a(cosπ/2 - cos3π/2) = - a π
Regards,
Team,
TopperLearning.
Answered by | 05 Feb, 2010, 10:57: AM
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