JEE Class main Answered
plz solve the question shown below
Asked by sarveshvibrantacademy | 19 Mar, 2019, 11:03: AM
Expert Answer
As we move the tube starting from minimum intensity , we get maximum intensity at some position and
moving further again we get minimum intensity so on.
In figure let us denote the minimum intensity as ' o ' and maximum intensity as ' x '.
If we get 10 maximum and then reaches the final minimum for 5 cm tube movement, then as shown in figure
we get a path difference of 10 cm between the starting minmum and final 10th minimum.
we need to consider the path difference 10 cm , because of two limbs, path difference becomes 10 cm when tube is moved by 5 cm.
Hence one minimum to subdequent minimum distance = [ 2(n+1) -1](λ/2) - [2n-1] (λ/2) = λ = 1 cm
Hence wavelength of sound is 1 cm .
Answered by Thiyagarajan K | 19 Mar, 2019, 03:20: PM
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