plz answer this question
Asked by | 9th Mar, 2008, 04:12: PM
Expert Answer:
In The question provided by you" x+3y=6
2x-3y=12
draw the graph and find the area of region bounded by
x=0, y=0, and 2x-3y=12" you have not mentioned the why is the equ x+3y=6 given.
For finding the area bounded by the lines x=0, y=0, and 2x-3y=12 , x =0 and y =0 represents y axis and x axis and the equation represents a line which intersects the x axis at 6 and y axis at -4 so the region is a right triangle with lb =6 and height 4 so area is =12 sq units
x=0, y=0, and 2x-3y=12" you have not mentioned the why is the equ x+3y=6 given.
For finding the area bounded by the lines x=0, y=0, and 2x-3y=12 , x =0 and y =0 represents y axis and x axis and the equation represents a line which intersects the x axis at 6 and y axis at -4 so the region is a right triangle with lb =6 and height 4 so area is =12 sq units
Answered by | 9th Mar, 2008, 11:00: PM
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