Pls solve

Asked by pankaj.shukla2 | 5th Jul, 2018, 12:45: PM

Expert Answer:

begin mathsize 16px style open parentheses cube root of straight a close parentheses to the power of 2 over 3 end exponent open parentheses fourth root of straight b close parentheses to the power of 1 fourth end exponent open parentheses root index 7 of straight c close parentheses to the power of 3 over 2 end exponent equals straight a to the power of straight x cross times straight b to the power of straight y cross times straight c to the power of straight z
open parentheses straight a to the power of 1 third end exponent close parentheses to the power of 2 over 3 end exponent open parentheses straight b to the power of 1 fourth end exponent close parentheses to the power of 1 fourth end exponent open parentheses straight c to the power of 1 over 7 end exponent close parentheses to the power of 3 over 2 end exponent equals straight a to the power of straight x cross times straight b to the power of straight y cross times straight c to the power of straight z
straight a to the power of 2 over 9 end exponent cross times straight b to the power of 1 over 16 end exponent cross times straight c to the power of 3 over 21 end exponent equals straight a to the power of straight x cross times straight b to the power of straight y cross times straight c to the power of straight z
straight x equals 2 over 9 comma space straight y equals 1 over 16 comma space straight z equals 3 over 21 end style

Answered by Sneha shidid | 6th Jul, 2018, 10:34: AM