lm√(x^l/x^m)*mn√(x^m/x^n)*nl√(x^n/x^l)

Asked by debjganguly | 26th Sep, 2020, 06:24: PM

Expert Answer:

To solve: lm√(xl/xm)*mn√(xm/xn)*nl√(xn/xl)
 
l m square root of x to the power of l over x to the power of m end root cross times m n square root of x to the power of m over x to the power of n end root cross times ln square root of x to the power of n over x to the power of l end root
equals open parentheses l m close parentheses open parentheses m n close parentheses open parentheses ln close parentheses square root of x to the power of l over x to the power of m cross times x to the power of m over x to the power of n cross times x to the power of n over x to the power of l end root
equals l squared m squared n squared square root of 1
equals l squared m squared n squared

Answered by Renu Varma | 28th Sep, 2020, 11:40: AM