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PLS NEED A QUICK SOLUTION FOR THE ATTACHED QUESTION
Asked by shyluraja21 | 04 Oct, 2021, 04:32: PM
1. According to the corresponding distance - time values we can see that the car travels equal distances in equal intervals of time. Thus, the car is moving in uniform motion.
The car is thus moving with constant speed = distance/ time = 20/10 = 2 m/s

2. According to the given velocity - time values, the v-t graph will be as follows: -

i) According to this v-t graph, we can see that velocity goes on increasing uniformly. Thus, the bus is moving with uniform acceleration.
ii) The initial velocity of bus is 5 m/s
iii) Acceleration of bus during the time interval t =0s to t = 25 s is,

iv) Distance travelled = Area under curve of v-t
or we can calculate the same using the thrid equation of motion
v2 - u2 = 2as
v = 30 m/s, u = 5m/s
a = 1 m/s2
Thus,
302 - 52 = 2 (1) x s
s = 875/2 = 437.5 m
Answered by Shiwani Sawant | 04 Oct, 2021, 08:03: PM

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