Asked by sanskritforall | 9th Mar, 2010, 08:24: PM
Let X and Y be the amounts of the two solutions respectively to be mixed.
Now the total acid amount in mixed should be same as total of that coming from individual solutions.
0.5X + 0.25Y = 0.4(10) = 4 ... (1)
Similarly the total water amount in the mixed solution should also balanced with the total of water amounts from individual solutions.
First solution is 50% acid so remainin 50% is water.
0.5X + 0.75Y = 0.6(10) = 6 .... (2)
Solving the two equations,
Y = 4 lit, and hence X = 10-4 = 6 lit.
Hence 6 lit of 50% and 4 lit of 25% acid solutions to be mixed.
Answered by | 10th Mar, 2010, 06:05: AM
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