JEE Class main Answered
PLEASE SOLVE
![question image](https://images.topperlearning.com/topper/new-ate/topr_20491356341302206DDDVVV.jpeg)
Asked by defence | 21 May, 2019, 11:05: AM
Starting from P at the end of third turn motorist reaches S the displacement is PS which is PO+0S
As this shape is regular hexagon therefore the triangles formesd are equilateral triangle
and hence PO=PQ=QO=500m. Therefore displacement is PO+OS=1000m.
Whereas, Distance =PQ+QR+RS=500+500+500=1500m
At the end of the sixth turn the motorist reaches the same point P. therefore Displacement=0 and
Distance = ![500 cross times 6 equals 3000 m](https://images.topperlearning.com/topper/tinymce/cache/4ab913659d573b51a807ce974afe5245.png)
![500 cross times 6 equals 3000 m](https://images.topperlearning.com/topper/tinymce/cache/4ab913659d573b51a807ce974afe5245.png)
At the end of the eighth turn the motorist reaches the point R so total displacement would be PR
![P R equals square root of P Q squared plus Q R squared plus 2 open parentheses P Q close parentheses open parentheses Q R close parentheses C o s theta end root
P R equals square root of 500 squared plus 500 squared plus 2 open parentheses 500 close parentheses open parentheses 500 close parentheses C o s 60 to the power of 0 end root](https://images.topperlearning.com/topper/tinymce/cache/3fe3f5035b5bb51af0ca6859cc642201.png)
![P R equals 500 square root of 3](https://images.topperlearning.com/topper/tinymce/cache/6da12c08090d0b73e92e64dceb9949b4.png)
Distance =![500 cross times 8 equals 4000 m](https://images.topperlearning.com/topper/tinymce/cache/e52ba5c337f82f26ecfccd3ebad30a57.png)
![500 cross times 8 equals 4000 m](https://images.topperlearning.com/topper/tinymce/cache/e52ba5c337f82f26ecfccd3ebad30a57.png)
Answered by Utkarsh Lokhande | 21 May, 2019, 14:23: PM
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