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Please solve without using L'hopital rule
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Asked by g_archanasharma | 05 Mar, 2019, 18:33: PM
answered-by-expert Expert Answer
begin mathsize 12px style L space equals space limit as x rightwards arrow straight pi of fraction numerator sin 3 x space minus space 3 sin x over denominator open parentheses straight pi minus straight x close parentheses cubed end fraction space equals space space limit as x rightwards arrow straight pi of fraction numerator negative 4 space sin cubed x over denominator open parentheses straight pi minus straight x close parentheses cubed end fraction l e t space left parenthesis straight pi minus straight x right parenthesis space equals space straight theta straight L space equals space limit as straight theta rightwards arrow 0 of fraction numerator negative 4 space sin cubed open parentheses straight pi minus straight theta close parentheses over denominator straight theta cubed end fraction space equals space limit as straight theta rightwards arrow 0 of space minus fraction numerator 4 sin cubed straight theta over denominator straight theta cubed end fraction space equals space minus 4 end style
Answered by Thiyagarajan K | 06 Mar, 2019, 01:18: AM

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