ICSE Class 8 Answered
Please solve this doubt
Asked by Cl_narayan | 26 Jun, 2019, 08:43: PM
Expert Answer
ABCD is a parallelogram.
angle ABC + angle DCB = 180° interior angles supplementary
11x - 2 + 15x = 180°
26x = 182°
x = 7
angle BCD= 15x = 105°
angle BCD + angle ECD = 180° liner pair
105° + angle ECD = 180°
angle ECD = 75°
In triangle CED,
angle ECD + angle CDE + angle DEC = 180°
75° + y + 90° = 180°
y = 15°
Answered by Sneha shidid | 27 Jun, 2019, 09:45: AM
ICSE 8 - Maths
Asked by Cl_narayan | 15 Jul, 2019, 09:00: AM
ANSWERED BY EXPERTICSE 8 - Maths
Asked by Cl_narayan | 26 Jun, 2019, 08:43: PM
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