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Please solve the problem in the picture as soon as possible.... with steps.

Asked by miaowmira1900 | 16 Aug, 2019, 01:35: AM

Fig.(1) shows steps to get Thevenin resistance. we need to open the current source and short the voltage source.
As shown in figure, Thevenin resistance is 6Ω
Fig.(2) shows the procedure to get Thevenin voltage.
By knowing the division of current at node marked as voltage point V1 ,
we get i = ( 2 - io ) A ...................(1)
Let the point b is at reference point and it can be assumed as zero potential
then V1 = 4 io ........................(2)
V1-V2 = 10io + 2i ...............................(3)
using eqn.(1) and eqn.(2), eqn.(3) is rewritten as 4io - V2 = 10io + 2(2- io ) ...........................(3)
or Thevenins voltage V2 = -4(io + 1)
Answered by Thiyagarajan K | 16 Aug, 2019, 11:47: AM
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