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CBSE Class 12-science Answered

Please solve the following
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Asked by Balbir | 27 Feb, 2018, 09:11: PM
answered-by-expert Expert Answer
Let us assume we have initially 1 μC at A. Let us bring 1 μC from infinity to the point B and the workdone w1 is given by
 
begin mathsize 12px style w 1 space equals space fraction numerator 1 over denominator 4 pi epsilon subscript 0 cross times 0.1 end fraction space equals fraction numerator 2.5 over denominator pi epsilon subscript 0 end fraction J end style
Let us bring another charge -4 μC from infinity to C and the workdone w2 is given by

begin mathsize 12px style w 2 space equals space fraction numerator negative 4 over denominator 4 pi epsilon subscript 0 cross times 0.1 end fraction space plus space fraction numerator negative 4 over denominator 4 pi epsilon subscript 0 cross times 0.1 end fraction equals fraction numerator negative 20 over denominator pi epsilon subscript 0 end fraction J end style
 
total workdone to assemble the charge configuration w1+w2 = -17.5/(πε0) Joules
 
Same amount of energy has to be spent to dismantle the charge configuration
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