Please solve the following question

Asked by Balbir | 7th Oct, 2017, 11:01: PM

Expert Answer:

begin mathsize 16px style integral fraction numerator dx over denominator fourth root of 1 plus straight x to the power of 4 end root end fraction
fraction numerator begin display style fourth root of 1 plus straight x to the power of 4 end root end style over denominator straight x end fraction equals straight t
using space division space rule space of space derivative space
dx equals fraction numerator 1 over denominator begin display style fraction numerator straight x squared over denominator begin display style open parentheses 1 plus straight x to the power of 4 close parentheses to the power of 3 over 4 end exponent end style end fraction minus fraction numerator begin display style fourth root of 1 plus straight x to the power of 4 end root end style over denominator straight x squared end fraction end style end fraction dt
integral fraction numerator negative straight t squared over denominator straight t to the power of 4 minus 1 end fraction dt
minus integral fraction numerator begin display style straight t squared end style over denominator begin display style open parentheses straight t plus 1 close parentheses open parentheses straight t minus 1 close parentheses open parentheses straight t squared plus 1 close parentheses end style end fraction dt
Using space partial space fraction space you space can space solve space it space further.
end style

Answered by Sneha shidid | 18th Dec, 2017, 10:51: AM

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