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ICSE Class 10 Answered

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Asked by siddharthjaiswal1122 | 16 Feb, 2019, 11:50: AM
answered-by-expert Expert Answer
Let a be the first term and d is the common difference
 
Second term of A.P. + Seventh term of A.P =  t2 + t7 = (a +d)+ [ a+6d ] = 2a + 7d = 30 ....................(1)
 
15th term = t15 = a + 14d  
8th term = t8 = a+7d
 
It is given that, t15 +1 = 2×t8  ;  hence  a+14d+1 = 2×(a+7d)  = 2a+14d   or    a = 1
 
By using the value of first term in eqn.(1), we get d = 4
 
Hence A.P is with first term a = 1 and common difference d = 4
Answered by Thiyagarajan K | 16 Feb, 2019, 07:20: PM
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