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Please give solution of the given figure.
![question image](https://images.topperlearning.com/topper/new-ate/topr_216224163208366714122019191418.jpeg)
Asked by anshuman.anshuman090 | 12 May, 2019, 19:17: PM
![](https://images.topperlearning.com/topper/tinymce/imagemanager/files/6f2c1be5413841b24b85033da849938c5cd8410f620c68.30828751may1201.png)
(1) Electric field E(r) = 0 , r < a ; Electric Field is zero inside spherical shell
(2) Electric field E(r) = 0 , a < r < b ; electric Field is zero inside Conductor
(3) Electric field E(r) =
, b < r < c ; Electric field is due to net charge on inner sphere.
![begin mathsize 12px style fraction numerator plus 2 q over denominator 4 πε subscript 0 space straight r squared end fraction end style](https://images.topperlearning.com/topper/tinymce/cache/6fe3ef920ce170a0fcf599b81adcbc08.png)
Outer spherical shell will not give electric field in this radial position.
(4) Electric field E(r) = 0 , c < r< d ; electric Field is zero inside Conductor
(5) Electric field E(r) =
, r >d ; Electric field is due to net charge on both sphere.
![begin mathsize 12px style fraction numerator plus 6 q over denominator 4 πε subscript 0 space straight r squared end fraction end style](https://images.topperlearning.com/topper/tinymce/cache/4272a2eacc3ffca82e5e6d7de4eb004d.png)
Graph of electrci field as a function of radial distance is shown in figure.
(a) charge on inner surface of small shell is zero
(b) charge on outer surface of small shell is +2q
(c) charge on inner surface of large shell is -2q (induced charges due to charge on small shell )
(d) charge on outer surface of large shell is +6q ( net charge on large shell is +4q)
Answered by Thiyagarajan K | 12 May, 2019, 21:39: PM
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