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Please give me solution of this question question

Asked by sanjaysingh.srct | 02 Sep, 2019, 22:59: PM

Expert Answer

The two lines are along the vectors

open parentheses i with hat on top minus j with hat on top plus k with hat on top close parentheses space a n d space open parentheses i with hat on top plus j with hat on top minus k with hat on top close parentheses space r e s p e c t i v e l y

A n g l e space b e t w e e n space t h e s e space t w o space l i n e s space equals space cos to the power of negative 1 end exponent open parentheses fraction numerator 1 cross times 1 plus 1 open parentheses negative 1 close parentheses plus open parentheses negative 1 close parentheses 1 over denominator square root of 3 square root of 3 end fraction close parentheses equals cos to the power of negative 1 end exponent 1 third N o w comma space v e c t o r space a lo n g space a c u t e space b i s e c t o r equals lambda open parentheses fraction numerator open parentheses i with hat on top minus j with hat on top plus k with hat on top close parentheses over denominator square root of 3 end fraction minus fraction numerator open parentheses i with hat on top minus j with hat on top plus k with hat on top close parentheses over denominator square root of 3 end fraction close parentheses equals fraction numerator 2 lambda over denominator square root of 3 end fraction open parentheses negative j with hat on top plus k with hat on top close parentheses H e n c e comma space t h e space e q u a t i o n space o f space a c u t e space a n g l e space b i s e c t o r space equals open parentheses i with hat on top plus 2 j with hat on top plus 3 k with hat on top close parentheses plus rho open parentheses j with hat on top minus k with hat on top close parentheses

Answered by Renu Varma | 18 Sep, 2019, 10:12: AM

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