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NEET Class neet Answered

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Asked by Prashant DIGHE | 14 Jan, 2020, 10:10: PM
answered-by-expert Expert Answer
If half life of sample-A is 1 year , its decay constant λA = ln2 (year)-1
 
If half life of sample-B is 1 year , its decay constant λA = ( ln2 )/2 = 0.5 × ln2 (year)-1
 
Let initially ytaken 10 g of sample-A and 1 g of sample-B has reached same activity after t years.
 
Then we have,  10 e-ln2 t = e-0.5 ln2 t
 
i.e., e.5 ln2 t  = 10    or   t = 2 × ( ln10 / ln 2 ) = 6.64 years
Answered by Thiyagarajan K | 15 Jan, 2020, 07:44: AM
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