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Asked by Prashant DIGHE | 08 Oct, 2019, 21:42: PM
answered-by-expert Expert Answer
Let Pa is atmospheric pressure
 
density of liquid d2 is twice of mercury density 13.6 g/cm3
 
Pressure P1 = Pa + 2×(25 cm of mercury pressure)
 
density of liquid d1 is mercury density 13.6 g/cm3
 
Pressure P2 = P1 + 26 cm of mercury pressure = Pa + 76 cm of mercury pressure
 
since atmospheric pressure Pa is 76 cm of mercury pressure,  we get pressure at closed limb of u-tube,  p = 2 Pa
Answered by Thiyagarajan K | 09 Oct, 2019, 10:16: AM

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