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NEET Class neet Answered

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Asked by Prashant DIGHE | 24 Apr, 2020, 10:10: PM
answered-by-expert Expert Answer
when engine is on , rocket moves up with uniform velocity v for time to so that vertical distance ho
moved with uniform speed is  ( v to ) .
 
After time to , engine is off, hence rocket will move with initial speed v in gravitaional field  and
travels some vertical distance till its speed comes to zero.
 
Vertical distance travelled by rocket when engine is off ,  h  = (v2 / 2g )
 
Hence total height reached by rocket = ho + h  = v to + [ v2 / (2g) ]
Answered by Thiyagarajan K | 25 Apr, 2020, 08:38: AM
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