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Asked by Prashant DIGHE | 08 Oct, 2019, 09:41: PM
answered-by-expert Expert Answer
Pressure at B, at half of depth of lake, PB = 10ρg  ................(1)
where ρ is density of water.
 
If pressure PC at water is 4/3 times of PB , then PC = (40/3)ρg  ...............(2)
 
pressure difference , PC - PB = ρg (h/2) = [ (40/3) - 10 ] ρg ..................(3)
where h is depth of lake
 
from eqn.(3) we get,  h = (20/3) m  =  6.67 m
Answered by Thiyagarajan K | 09 Oct, 2019, 09:49: AM
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