Please answer this question

Asked by Abhijeetoo7 | 7th Jul, 2008, 11:16: AM

Expert Answer:

Consider x3+y3+z3-3xyz

= (x+y+z)(x2+y2+z2-xy-yz-zx)

Now, since x+y+z = 0

thus, x3+y3+z3-3xyz =0

this implies that x3+y3+z3=3xyz

dividing throughout by xyz, we get

Answered by  | 15th Jul, 2008, 09:15: AM

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