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Asked by Krisheeea9 | 17 Aug, 2020, 23:50: PM
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A s space p e r space t h e space g u a s s apostrophe s space t h e o r e m space E with rightwards arrow on top times stack d s with rightwards arrow on top equals Q subscript e n c l o s e d end subscript over epsilon subscript r A t space r less than space 2 m comma space A s space n o space c h a r g e space i n space t h i s space s u r f a c e Q subscript e n c l o s e d end subscript equals 0 T h e r e f o r e space e l e c t r i c space f i e l d space i s space 0 A t space 2 m less than r less than 4 m E with rightwards arrow on top times 2 πrl equals fraction numerator rho open parentheses straight pi 2 squared straight l minus πr squared straight l close parentheses over denominator epsilon subscript r end fraction E with rightwards arrow on top times 2 r equals fraction numerator rho open parentheses 2 squared minus r squared close parentheses over denominator epsilon subscript r end fraction E with rightwards arrow on top equals fraction numerator rho open parentheses 2 squared minus r squared close parentheses over denominator 2 r space epsilon subscript r end fraction A t space r greater than 4 m E with rightwards arrow on top times 2 πrl equals fraction numerator rho open parentheses straight pi 4 squared straight l minus pi 2 squared straight l close parentheses over denominator epsilon subscript r end fraction E with rightwards arrow on top times 2 r equals fraction numerator rho open parentheses 4 squared minus 2 squared close parentheses over denominator epsilon subscript r end fraction E with rightwards arrow on top equals fraction numerator rho open parentheses 4 squared minus 2 squared close parentheses over denominator 2 r epsilon subscript r end fraction
Answered by Utkarsh Lokhande | 20 Aug, 2020, 22:07: PM

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