NEET Class neet Answered
please answer this (Q.8)
![question image](https://images.topperlearning.com/topper/new-ate/topr_4740547141738668P202004242123281.jpeg)
Asked by Prashant DIGHE | 24 Apr, 2020, 22:00: PM
Let the ball take t seconds to reach ground.
Velocity at (t-1) second = g(t-1)
Distance S travelled in last one second is obtained from the equation of motion ,
S = ut +(1/2)g t2 by substituting t = 1 and intial speed u = g(t-1)
Distance travelled in last second = g(t-1) +(1/2)g = 55
By substituting g = 10 m/s2 , we get from above equation , t = 5 s
Height of tower h = (1/2) g t2 = (1/2)×10×25 = 125 m
-------------------------------------------
When a thrown object vertically travels equal distance in 5th second and 6th second means , it reaches maximum
height after 5th second and travels downward at 6th second
Hence projection velocity to reach maximum height at t=5 second , u = g t = 9.8 × 5 = 49 m/s
Answered by Thiyagarajan K | 25 Apr, 2020, 09:06: AM
Application Videos
Concept Videos
NEET neet - Physics
Asked by cmashudrana | 26 Jul, 2024, 10:51: AM
NEET neet - Physics
Asked by upparmanjunath70 | 19 Jul, 2024, 22:26: PM
NEET neet - Physics
Asked by zfaima704 | 19 Jul, 2024, 14:29: PM
NEET neet - Physics
Asked by shaikmuneerjaan | 18 Jul, 2024, 20:58: PM
NEET neet - Physics
Asked by nk4746870 | 15 Jul, 2024, 21:21: PM
NEET neet - Physics
Asked by dasmyton | 09 Jul, 2024, 22:46: PM
NEET neet - Physics
Asked by shobhaguduru02 | 09 Jul, 2024, 20:21: PM
NEET neet - Physics
Asked by kashinathpaikrao89446 | 09 Jul, 2024, 10:46: AM
NEET neet - Physics
Asked by dshyamala44 | 08 Jul, 2024, 21:05: PM
NEET neet - Physics
Asked by jagadishshnkr | 08 Jul, 2024, 20:50: PM