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Asked by miaowmira1900 | 15 Feb, 2020, 20:33: PM
answered-by-expert Expert Answer
power delivered by left side AC voltage source = vm im cosφ
 
where φ is phase difference between current and voltage
 
im = vm / z  , where z is impedence = ( 452 + 22 ) ≈ 45 Ω
 
Phase difference φ = tan-1(-45/2) = -87.5o
 
Since left side source voltage already has a phase 50o , actual phase difference = (50 - 87.5) = -37.5o
 
Hence power delivered by left side AC voltage source = 10 × ( 10/45) cos(-37.5) ≈ 1.763 W
 
--------------------------------------------------------------------------------
 
Similarly power delivered by right side AC voltage source = vm im cosφ
 
where φ is phase difference between current and voltage
 
im = vm / Z  , where z is impedence = ( 1002 + 22 ) ≈ 100 Ω
 
Phase difference φ = tan-1(100/2) = 89o
 
Hence power delivered by right side AC voltage source = 10 × ( 10/45) cos(89) ≈ 0.04 W
 
Hence total power delivered to passive element 2Ω resistance = ( 1.763+ 0.04 ) W = 1.80 W


Answered by Thiyagarajan K | 18 Feb, 2020, 09:44: AM

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