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CBSE Class 12-science Answered

Plaese answer the following question
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Asked by Balbir | 27 Feb, 2018, 09:20: PM
answered-by-expert Expert Answer
Potential at P begin mathsize 12px style equals space fraction numerator 1 over denominator 4 pi epsilon subscript 0 end fraction open parentheses fraction numerator negative q over denominator square root of 7 squared plus a squared end root end fraction space plus space fraction numerator plus q over denominator square root of 7 squared plus a squared end root end fraction close parentheses space equals space 0 end style
Potential at Q  begin mathsize 12px style equals space fraction numerator 1 over denominator 4 pi epsilon subscript 0 end fraction open parentheses fraction numerator negative q over denominator square root of 3 squared plus a squared end root end fraction space plus space fraction numerator plus q over denominator square root of 3 squared plus a squared end root end fraction close parentheses space equals space 0 end style
since Potential at P and Q are zero, there is no potential difference between the points P and Q.
Hence workdone also zero while moving test charge from P to Q
Answered by Thiyagarajan K | 28 Feb, 2018, 06:26: AM

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