CBSE Class 12-science Answered
Parabola
Asked by | 08 Jan, 2010, 07:28: PM
Expert Answer
y2 = 4a ( x + a)
(2y)dy/dx = 4a
dy/dx = 2a/y
Orthoganal trajectories of the curve will be given by:
-1/ (dy/dx) = 2a/y
-dx/dy = 2a/y
-dx = (2a/y )dy.......(1)
Integrating we get
y = ce(-x/2a), where c is the integrating constant.
Answered by | 09 Jan, 2010, 11:44: AM
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