MID PTS THEOREM
Asked by | 13th Sep, 2009, 06:44: AM
let ABCD be a parallelogram.
E,F,G,H be the mid points of the sides AB,BC,CD,DA.
EH II BD...
EH =1/2[BD]....mid pt thm
FG II BD and FG=1/2[BD]
EH II FG
EFGH is a parallelogram....one pair of opp sides is parallel and equal
so FH and EG become the diagonals of this parallelogram, so they must bisect each other.
Answered by | 13th Sep, 2009, 08:46: AM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Verify mobile number
Enter the OTP sent to your number