MID PTS THEOREM

Asked by  | 13th Sep, 2009, 06:44: AM

Expert Answer:

let ABCD be a parallelogram.

E,F,G,H be the mid points of the sides AB,BC,CD,DA.

join BD.

EH   II BD...

and

EH =1/2[BD]....mid pt thm

Simly

FG II BD and FG=1/2[BD]

So EH=FG

and

EH II FG

So

EFGH is a parallelogram....one  pair of opp sides is  parallel and equal

so FH and EG become the diagonals of this parallelogram, so they must bisect each other.

Answered by  | 13th Sep, 2009, 08:46: AM

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