CBSE Class 12-science Answered
kindly answer
Asked by arup.isro | 25 Jun, 2019, 11:24: PM
Expert Answer
As shown in fig.1, we need to connect 4 capacitors in series to get potential difference less than 300 V
across each capacitor, if the the potential difference across the combination is 1000 V.
Equivalent capacitance of 4 capacitors of each of capacitance 1 μf in series is 0.25 μf.
Since we need 2 μf capacitance we need to connect 32 capacitors as shown in figure 2,
so that 8 group of capacitor combination are connected in parallel and each group consists of
4 capacitors connected in series
Answered by Thiyagarajan K | 26 Jun, 2019, 10:35: AM
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