JEE Class main Answered
Kindly answer the question in the attached picture
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Asked by maps.stuti | 03 Jan, 2022, 08:19: AM
![](https://images.topperlearning.com/topper/tinymce/imagemanager/files/fc2d66c2df1324b912afb3e96ef257f961d281816d5ce2.16727927f8.png)
Tension forces acting on string at various points are shown in figure.
If the 4 kg block moves down Δl downwards , length of string EF increases by Δl , length between E and A decreases by Δl and length between O and A increases by Δl .
Hence length between B and C decreases by Δl .
Hence magnitude of acceleration of 4 kg block and magnitude of acceleration of 2 kg block are equal.
Free body diagram for 2 kg block on inclined surface and free body diagram of 4 kg block are shown in figure.
By applying Newton's law to the 2 kg block, we get
T - ( 2 g sin30 ) = 2 a
T - g = 2a ..............................(1)
where a is acceleration of the system
By applying Newton's law to the 4 kg block , we get
4g - 2T = 4a ................................(2)
By multiplying eqn.(1) by 2 and adding eqn.(2) , we eliminate tension T and we get
acceleration a = (1/4) g
If we consider acceleration due to gravity g = 10 m/s2 , then acceleration a = 5/2 m/s2
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