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Kindly answer the question in the attached picture
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Asked by maps.stuti | 03 Jan, 2022, 08:19: AM
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Tension forces acting on string at various points are shown in figure.
 
If the 4 kg block moves down Δl downwards , length of string EF increases by Δl ,  length between E and A decreases by Δl and length between O and A increases by Δl .
 
Hence length between B and C decreases by Δl .
 
Hence magnitude of acceleration of 4 kg block and magnitude of acceleration of 2 kg block are equal.
 
Free body diagram for 2 kg block on inclined surface and free body diagram of 4 kg block are shown in figure.
 
By applying Newton's law to the 2 kg block, we get
 
T - ( 2 g sin30 ) = 2 a
 
T - g = 2a   ..............................(1)
 
where a is acceleration of the system
 
By applying Newton's law to the 4 kg block , we get
 
4g - 2T = 4a ................................(2)
 
By multiplying eqn.(1) by 2 and adding eqn.(2) , we eliminate tension T and we get
 
acceleration a  = (1/4) g
 
If we consider acceleration due to gravity g = 10 m/s2  , then acceleration a = 5/2 m/s2
Answered by Thiyagarajan K | 03 Jan, 2022, 10:48: AM
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