NEET Class neet Answered
is u²/4g is one of the formula to find max height of the projectile??
Asked by khazinawaz89 | 20 Oct, 2021, 20:05: PM
Expert Answer
Maximum height hmax of the projectile is determined from the following equation
............................ (1)where u is initial projection velocity at angle θ from horizontal and g is acceleration due to gravity.
We get maximum range , i.e., maximum distance travelled horizontally when angle of projection θ is 45o
If we substitute θ = 45o , then we get from eqn.(1)
............................(2)Hence we can consider eqn.(2) as maximum height when projectile is projected for maximum range ,
i.e.when angle of projection is 45o , we get maximum height from eqn.(2)
Answered by Thiyagarajan K | 20 Oct, 2021, 20:34: PM
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