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is u²/4g is  one of the formula to find max height of the projectile??
Asked by khazinawaz89 | 20 Oct, 2021, 08:05: PM
Maximum height hmax of the projectile is  determined from the following equation

............................ (1)
where u is initial projection velocity at angle θ from horizontal and g is acceleration due to gravity.

We get maximum range , i.e., maximum distance travelled horizontally when angle of projection θ is 45o

If we substitute θ = 45o , then we get from eqn.(1)

............................(2)
Hence we can consider eqn.(2) as maximum height when projectile is projected for maximum range ,
i.e.when  angle of projection is 45o , we get maximum height from eqn.(2)
Answered by Thiyagarajan K | 20 Oct, 2021, 08:34: PM
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