Intg dx/(sqrt(7-3x-x^2))
Asked by Anuradha Pradeep | 6th Nov, 2012, 11:04: AM
Expert Answer:
7 - 3x - x2 = 7 - (x2 + 3x + 9/4 - 9/4)
= 7 + 9/4 - (x + 3/2)2
= 37/4 - (x + 3/2)2
Thus, we have:
Integral dx/(sqrt(7-3x-x^2))
= Integral dx/sqrt(37/4 - (x + 3/2)2)
Put x + 3/2 = t, so dx = dt
Integral dx/sqrt(37/4 - (x + 3/2)2) = Integral dt/sqrt(37/4 - (t)2)
This integral can now easily be evaluated.
Answered by | 6th Nov, 2012, 07:51: PM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change