CBSE Class 12-science Answered
Integration sum
Asked by | 28 Jan, 2010, 05:25: AM
Expert Answer
Put x = b tany
dx = bsec2y dy
and b2+x2 = b2(1+tan2y) = b2sec2y
Hence (b2+x2 )3/2= b3sec3y
b sec2y dy/b3sec3y = dy/b2secy = cosy dy/b2 = siny/b2 + c
= (sin(tan-1(x/b)))/b2 + c
Regards,
Team,
TopperLearning.
Answered by | 29 Jan, 2010, 10:09: AM
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