Integration sum

Asked by  | 28th Jan, 2010, 05:25: AM

Expert Answer:

Put x = b tany

dx = bsec2y dy

and b2+x2 = b2(1+tan2y) = b2sec2y

Hence (b2+x2 )3/2= b3sec3y

b sec2y dy/b3sec3y = dy/b2secy = cosy dy/b2 = siny/b2 + c

= (sin(tan-1(x/b)))/b2 + c

Regards,

Team,

TopperLearning.

Answered by  | 29th Jan, 2010, 10:09: AM

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