Integrate: Sin[x-a]/Sinx dx

Asked by  | 12th Dec, 2008, 08:23: PM

Expert Answer:

Expand the integrand as

Sin(x-a)/Sinx=(SinxCosa-CosxSina)/Sinx

So, I=

=

=xcosa -{sinaloglsinxl}+c

Answered by  | 13th Dec, 2008, 08:34: AM

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