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integrate e^2x-1/e^2x+1 dx
Asked by | 27 Aug, 2012, 07:39: PM Expert Answer
Multiply the given function by e^(-x), we get,

(e^2x - 1) / (e^2x + 1) =
(e^x-e^-x)/(e^x+e^-x)

Integral (e^x-e^-x)/(e^x+e^-x) dx =
Integral 1/(e^x+e^-x) d(e^x+e^-x) =
log(e^x+e^-x)+C
Answered by | 28 Aug, 2012, 02:17: PM

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