Asked by | 18th Jan, 2010, 08:37: AM
The integral can be evaluated by substituting, cosx = (eix + e-ix)/2, and of the difficulty level which is not expected.
The solution involves polylogarithmic function, Lis(z).
The solution is,
x2i/2 - xlog(1+e2ix)+xlog cosx + i Lis(2,-e2ix) + C
Answered by | 18th Jan, 2010, 08:47: PM
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