Integral sec xcosec x/ log tanx dx

Asked by rraj.15266 | 27th Nov, 2017, 07:58: AM

Expert Answer:

begin mathsize 16px style integral fraction numerator secxcosecxdx over denominator log left parenthesis tanx right parenthesis end fraction
log left parenthesis tanx right parenthesis equals straight t
1 over tanx cross times sec squared xdx equals dt
cotx cross times fraction numerator 1 over denominator cos squared straight x end fraction dx equals dt
cosx over sinx cross times fraction numerator 1 over denominator cos squared straight x end fraction dx equals dt
1 over sinxcosx dx equals dt
secxcosecxdx equals dt
integral dt over straight t
Integrate space it space further. end style

Answered by Sneha shidid | 28th Nov, 2017, 12:18: PM