Increasing and Decreasing Functions

Asked by spuneet23 | 25th Aug, 2009, 04:52: PM

Expert Answer:

The function is increasing in the inetrval (0,2).

So, d is the correct option.

To get the solution following are the steps required:

y = x2 e-x

y' = 2x e-x - x2e-x

    = x e-x (2 - x)

For turning points, y' = 0

⇒ x = 0, 2,

for x = 0      y' < 0

for x = 2      y' > 0

So, in the interval the function y = x2 e-x is an incerasing function.

Similarly you can also deduce that in interval (-, 0) and (2,) the function is decreasing.

 

 

 

Answered by  | 26th Aug, 2009, 02:55: PM

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